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Honored Contributor
Posts: 54,451
Registered: ‎03-29-2012

For $1,055 these could be YOURS!

'Cornelia' Cutout Platform Wedge Sandal (Women)

{#emotions_dlg.scared}

Honored Contributor
Posts: 10,009
Registered: ‎07-28-2012

Re: For $1,055 these could be YOURS!

I'm getting 3 pair.

"To each their own, in all things".
Honored Contributor
Posts: 8,100
Registered: ‎03-17-2010

Re: For $1,055 these could be YOURS!

ROFL... tape those ankles....

*~"Never eat more than you can lift......" Miss Piggy~*
Esteemed Contributor
Posts: 7,752
Registered: ‎03-09-2010

Re: For $1,055 these could be YOURS!

I had a pair with that platform back in the late 70's

It's a wonder I didn't break my neck

It's God's job to judge the terrorists. It's our mission to arrange the meeting. U.S. Marines
Super Contributor
Posts: 4,044
Registered: ‎03-09-2010

Re: For $1,055 these could be YOURS!

{#emotions_dlg.lol} I was looking at those yesterday!

Those are Stella McCartney.

They are sold out in my size though, so I couldn't order. (JK).

Honored Contributor
Posts: 41,556
Registered: ‎03-12-2010

Re: For $1,055 these could be YOURS!

hahahahahahaha ROFL hahahahaha

There are many elements: wind, fire, water
But none quite like the element of surprise
Honored Contributor
Posts: 13,347
Registered: ‎07-25-2010

Re: For $1,055 these could be YOURS!

I'd like the see the old lady who lived in that shoe.

Trusted Contributor
Posts: 1,005
Registered: ‎03-09-2010

Re: For $1,055 these could be YOURS!

I used to clomp and stomp around in those - OK, maybe not quite that high but close enough. Must have looked totally ridiculous although at the time, they were quite the thing to wear.

Honored Contributor
Posts: 43,468
Registered: ‎01-08-2011

Re: For $1,055 these could be YOURS!

No way! The weight for one thing! It would be like walking through sand!

Respected Contributor
Posts: 4,532
Registered: ‎03-11-2010

Re: For $1,055 these could be YOURS!

On 1/30/2015 brewhaha said:

I'd like the see the old lady who lived in that shoe.


You never disappoint.